The two square faces of a rectangular dielectric slab (dielectric constant 4.0) of dimensions $20 c m \times 20 c m \times 1.0 m m$ are metal-coated. Find the capacitance between the coated surfaces.

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What is the thickness of the plating if the cathode consists of a sheet of metal 4.0 x 4.0 cm square which is coated on both faces? The density of nickel is 8.9 g/cm3. Mass of Nickel is 9.9 gm.

The correct option is B 0.035 cmArea of two faces =2×4×4=32The volume of 9.9 g Ni =massdensity=9.98.9=1.1Thickness of plating =1.1132=0.035 cmHence, option B is correct.

What is the thickness of the plating if the cathode consists of a sheet of metal 4.0 x 4.0 cm square which is coated on both faces? The density of nickel is 8.9 g/cm $^{3}$ . Mass of Nickel is 9.9 gm.

The correct option is B 0.035 cm
Area of two faces $= 2 \times 4 \times 4 = 32$

The volume of 9.9 g Ni $= \frac{m a s s}{d e n s i t y} = \frac{9.9}{8.9} = 1.1$

Thickness of plating $= \frac{1.11}{32} = 0.035 c m$

Hence, option B is correct.