Question

What is the third number which can form a Pythagorean triplet along with 11 and 60? (2 marks)

Answer 1

A Pythogorean triplet is a set of three positive integers a,b and c, which follows the rule
$a^2+b^2=c^2.$ (0.5 marks)
In the above given numbers, 11 and 60, if $a=11$ and $b=60,$ then
we can observe that
${11}^2+{60}^2=121+3600=3721={61}^2.$

Hence, the condition for a Pythagorean triplet is satisfied, if the third number is 61. (1.5 marks)