Question

What is the time (in/sec) taken by a 180 m long train running at 54 km/h to cross a man standing on a platform?

Answer 1

Distance = 180 m

speed = 54km/n=54000 m/n

Distance=$speed\times time$

$time=\frac{distance}{speed}$

$\frac{180}{54000}$hr

$\frac{180\times 60}{54000}min=0.2min$

= 12.5 sec