Question

What is the time taken by the galvanic cell which operates almost ideally under reversible conditions at a current of $\text{1}{\text{0}}^{-16}A$ to deliver 1 mole of electron?

Answer 1

$1$ $mol$ of $e^{-}=1$ $F=\frac{charge}{96500}$

$96500={10}^{-16}\times t$

$t=9.65\times {10}^{20}$ $s$