Question

What is the torque (in kNm) of a shaft , diameter 200 mm can safely transmit, if the shear stress is not to exceed 50 MPa

• A. 78.54
• B. 59.37
• C. 91.63
• D. 132.8

Answer 1

The correct option is A 78.54

${\tau }_{max}=\frac{16T}{\pi D^3}$

$\Rightarrow$ $50=\frac{16\times T}{\pi \times {200}^3}$

$\Rightarrow$ $T=78.54$ kNm