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Ways to Define Concentration

What is the t...

Question

What is the total hardness of water containing 68 ppm of $C a S O_{4}$ and 19 ppm of $M g C l_{2}$ ?

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Solution

$[C a C O_{3}]$
Equivalent $= \frac{100}{40} [C a^{+ 2}] + \frac{100}{24.3} [M g^{+ 2}]$
$= \frac{100}{40} \times 68 + \frac{100}{24.3} \times 19$
=170+78.18
=248.18

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