What is the total number of candidates at an examination if $31 %$ fail and the number of those who passed exceeds the number of those who failed by $247$ ?

605

No worries! We‘ve got your back. Try BYJU‘S free classes today!

560

No worries! We‘ve got your back. Try BYJU‘S free classes today!

650

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

None

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $650$
Failed candidates = $31$ %
Passed candidates = $69$ %
we have
$\frac{69 x}{100} - \frac{31 x}{100} = 247$
$\frac{38 x}{100} = 247$
$x = 650$

Suggest Corrections

Similar questions

Q. What is the total number of candidates at an examination, if 31 % fail and the number of failing students is 248.

Q. The average of marks obtained by

120

candidates was

35

. If average of the passed candidates was

39

and that of the failed candidates was

15

, then the number of those candidates, who passed the examination, was

Q. In an examination, the number of those who passed and the number of those who failed were in the ratio

25 : 4.

If five more had appeared and the number of failures were

2

less than earlier, the ratio of those passed to failures would be

22 : 3.

The number who appeared at the examination is

Q. The average of marks obtained by 120 condidates was 35. If the average of the passed candidates was 39 and that of the failed candidates was 15, then the number of those candidates who passed the examination was

In an examination, the number of those who passed and the number of those who failed was in the ratio of 3 : 1. Had 48 more appeared, and 8 more failed the ratio of passed to failures would have been 10 : 3. How many students appeared for the examination?

Join BYJU'S Learning Program

What is the total number of candidates at an examination if 31% fail and the number of those who passed exceeds the number of those who failed by 247?

The correct option is C 650Failed candidates = 31 %Passed candidates = 69%we have69x100−31x100=24738x100=247x=650

What is the total number of candidates at an examination if $31 %$ fail and the number of those who passed exceeds the number of those who failed by $247$ ?

The correct option is C $650$
Failed candidates = $31$ %
Passed candidates = $69$ %
we have
$\frac{69 x}{100} - \frac{31 x}{100} = 247$
$\frac{38 x}{100} = 247$
$x = 650$