Question

What is the total number of electrons present in 1.6 g of methane?

• A. $6.023\times {10}^{23}$
• B. 16
• C. $12.04\times {10}^{23}$
• D. $6.023\times {10}^{24}$

Answer 1

The correct option is D $6.023\times {10}^{24}$

$1$ mole of $C{H}_4=16g$

$16g$ of $C{H}_4$ contains $10$ electrons

$16g$ of $C{H}_4$ contains $=\frac{10}{16}\times 1.6\times 6.023\times {10}^{23}$

$=6.023\times {10}^{23}$ electrons.