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Isomerism

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Question

What is the total number of non-cyclic isomers possible of a compound having molecular formula $C_{5} H_{8}$ ?

A

7

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B

13

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C

11

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D

10

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Solution

The correct option is D 11
Total no. of isomers possible is 32 out of which there are 21 cyclic and 11 non-cyclic isomers are possible.
Option C is correct.

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