What is the total percentage of oxygen in magnesium nitrate crystals $(M g (N O_{3})_{2} .6 H_{2} O)$ ?
[ $O = 16, N = 14, H = 1, M g = 24$ ]

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Solution

The correct option is A 75
Molar mass of $M g (N O_{3})_{2} .6 H_{2} O$ $= 256.4 g$
So, % of oxygen $= 192 \times \frac{100}{256.4} = 75$

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Similar questions

Q. The total percentage of magnesium present in magnesium nitrate crystals

M g (N O_{3})_{2} .6 H_{2} O

is:
[

M g = 24; N = 14; O = 16; H = 1

Find the percentage of oxygen in magnesium nitrate crystals, $M g (N O_{3})_{2} .6 H_{2} O$ [Mg = 24, N = 14, O = 16, H = 1]

Find the total percentage of oxygen in magnesium nitrate crystal Mg(NO₃)₂·6H₂O.
[H = 1, N = 14, O = 16, Mg = 24]

Q. Find the total percentage of Magnesium in magnesium nitrate crystals:

[M g (N O_{3})_{2} 6 H_{2} O .

(M g = 24, O = 16

and

H = 1)

Find the percentage of
(a) oxygen in magnesium nitrate crystals $[M g (N O_{3})_{2} 6 H_{2} O]$ .
(b) boron in $N a_{2} B_{4} O_{7} . 10 H_{2} O . [H = 1, B = 11, O = 16, N a = 23] .$
(c) phosphorus in the fertilizer superphosphate $C a (H_{2} P O_{4})_{2}$

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What is the total percentage of oxygen in magnesium nitrate crystals(Mg(NO3)2.6H2O)? [O=16, N=14, H=1, Mg=24]

The correct option is A 75Molar mass of Mg(NO3)2.6H2O=256.4 gSo, % of oxygen =192×100256.4=75

What is the total percentage of oxygen in magnesium nitrate crystals $(M g (N O_{3})_{2} .6 H_{2} O)$ ?
[ $O = 16, N = 14, H = 1, M g = 24$ ]

The correct option is A 75
Molar mass of $M g (N O_{3})_{2} .6 H_{2} O$ $= 256.4 g$
So, % of oxygen $= 192 \times \frac{100}{256.4} = 75$