Question

What is the total pressure exerted by the mixture of 7.0 g of $N_2$, 2g of hydrogen and 8.0 g of sulphur dioxide gases in a vessel of 6.1L capacity that has been kept in a reservoir at ${27}^{o}C$?

• A. 2,5 bar
• B. 4.5 bar
• C. 10 atm
• D. 5.7 bar

Answer 1

Answer: (D)

5.7 bar

Total moles of gases $=(\frac{7}{28}+\frac{2}{2}+\frac{8}{64})=(\frac{1}{4}+\frac{1}{8}+1)=\frac{11}{8}$ moles.

volume of vessel $=6.1L$

and, temperature

$={27}^{\circ }C=300k$.

By ideal gas equation, $PV=nRT$.

$\begin{array}{cc}\Rightarrow P=\frac{nRT}{V}& =\frac{11\times 0.0831.x300}{6.1}bar.\\ & \approx 5.7bar.\end{array}$

Thus, total pressure exerted by the mixture $=5.7$ bar.

so, option (D) is correct.