Statements (a), (b) and (c) are correct, so total score = 4 + 1 + 3 = 8
(a) Any electrode having lower oxidation potential means it has less tendency to undergo oxidation or more tendency to undergo reduction. So it would be a stronger oxidizing agent. Hence, the statement is correct and the score is 4.
(b) If the oxidation potential of Zn vessel is more than the oxidation potential of the solution (AgNO3), then it will constitute a fesible cell and E⊖cell will be positive. So one cannot store the solution (AgNO3) in a vessel made up of Zn.
E⊖Zn|Zn2+=0.76V.
or
E⊖Zn2|Zn=−0.76V
E⊖Ag|Ag⊕=−0.80V
or
E⊖Ag|Ag⊕=0.80V
∴E⊖cell=(E⊖red)c−(E⊖red)a
= 0.80 - (-0.76) = 1.56 V
Hence, the statement is correct and the score is 1. Cell reperesent :
Zn|Zn2+||Ag⊕|Ag
(c) Representation of concentration cell :
Ag|Ag⊕(c1)||Ag⊕(c2)|Ag
Ag|Ag⊕(c1) behaves as anode and Ag|Ag⊕(c2) behaves as cathode. Hence, the statement is correct and the score is 3.
(d) The statement is wrong. Correct statement would be : If Pt electrodes act as cathode and Cu electrodes as anode. Since Cu from anode will give Cu2+ and dissolve in solution and same equivalent of Cu2+ from solution will be deposited on Pt electrodes, so [Cu2+] will remain constant.