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Other
Control Systems
Mathematical Modelling-2
What is the t...
Question
What is the transfer function for the network shown below
V
c
2
(
s
)
V
i
(
s
)
A
V
c
2
(
s
)
V
i
(
s
)
=
1
(
s
C
1
+
s
C
2
+
s
2
C
1
C
2
R
2
)
(
1
+
s
C
1
R
1
+
s
2
C
1
L
1
)
+
s
C
2
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B
V
c
2
(
s
)
V
i
(
s
)
=
s
C
1
(
s
C
1
+
s
C
2
+
s
2
C
1
C
2
R
2
)
(
1
+
s
C
1
R
1
+
s
2
C
1
L
1
)
−
s
C
2
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C
V
c
2
(
s
)
V
i
(
s
)
=
s
C
1
(
s
C
1
+
s
C
2
+
s
2
C
1
C
2
R
2
)
(
1
+
s
C
1
R
1
+
s
2
C
1
L
1
)
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D
V
c
2
(
s
)
V
i
(
s
)
=
1
(
s
C
1
+
s
C
2
+
s
2
C
1
C
2
R
2
)
(
1
+
s
C
1
R
1
+
s
2
C
1
L
1
)
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Open in App
Solution
The correct option is
B
V
c
2
(
s
)
V
i
(
s
)
=
s
C
1
(
s
C
1
+
s
C
2
+
s
2
C
1
C
2
R
2
)
(
1
+
s
C
1
R
1
+
s
2
C
1
L
1
)
−
s
C
2
Applying KVL in loop-1,
V
i
(
s
)
=
R
1
I
1
(
s
)
+
1
s
C
1
(
I
1
(
s
)
−
I
2
(
s
)
)
+
s
L
1
I
1
(
s
)
...(i)
V
i
(
s
)
=
I
1
(
s
)
[
R
1
+
1
s
C
1
+
s
L
1
]
−
I
2
(
s
)
s
C
1
...(ii)
Applying KVL in Loop-2
1
s
C
1
(
I
2
(
s
)
−
I
1
(
s
)
)
+
V
c
2
(
s
)
+
R
2
I
2
(
s
)
=
0
....(iii)
V
c
2
(
s
)
−
I
1
(
s
)
s
C
1
+
I
2
(
s
)
(
1
s
C
1
+
R
2
)
=0 ...(iv)
V
c
2
(
s
)
=
I
2
(
s
)
s
C
2
...(v)
∴
I
2
(
s
)
=
s
C
2
V
c
2
(
s
)
...(vi)
From equation (vi) and (iv), we get
V
c
2
(
s
)
−
I
1
(
s
)
s
c
1
+
s
C
2
V
c
2
(
1
s
C
1
+
R
2
)
=
0
...(vii)
I
1
(
s
)
=
s
C
1
V
c
2
(
s
)
(
1
+
s
C
2
(
1
s
C
1
+
R
2
)
)
...(viii)
I
1
(
s
)
=
s
C
1
V
c
2
(
s
)
(
s
C
1
+
s
C
2
+
s
2
C
1
C
2
R
2
s
C
1
)
...(ix)
I
1
(
s
)
=
V
c
2
(
s
)
(
s
C
1
+
s
C
2
+
s
2
C
1
C
2
R
2
)
....(x)
Substitue equation (vi) and equation (x) in equation (ii), we get
V
i
(
s
)
=
V
c
2
(
s
)
(
s
C
1
+
s
C
2
+
s
2
C
1
C
2
R
2
)
(
R
1
+
1
s
C
1
+
s
L
1
)
−
s
C
2
V
c
2
(
s
)
s
C
1
....(xi)
V
i
(
s
)
=
V
c
2
(
s
)
(
s
C
1
+
s
C
2
+
s
2
C
1
C
2
R
2
)
(
1
+
s
C
1
R
1
+
s
2
L
1
C
1
)
s
C
1
−
s
C
2
V
c
2
(
s
)
s
C
1
...(xiii)
The transfer function is
V
c
2
(
s
)
V
i
(
s
)
=
s
C
1
(
s
C
1
+
s
C
2
+
s
2
C
1
C
2
R
2
)
(
1
+
s
C
1
R
1
+
s
2
C
1
L
1
)
−
s
C
2
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0
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