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Question

What is the transfer function for the network shown below Vc2(s)Vi(s)

A
Vc2(s)Vi(s)=1(sC1+sC2+s2C1C2R2)(1+sC1R1+s2C1L1)+sC2
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B
Vc2(s)Vi(s)=sC1(sC1+sC2+s2C1C2R2)(1+sC1R1+s2C1L1)sC2
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C
Vc2(s)Vi(s)=sC1(sC1+sC2+s2C1C2R2)(1+sC1R1+s2C1L1)
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D
Vc2(s)Vi(s)=1(sC1+sC2+s2C1C2R2)(1+sC1R1+s2C1L1)
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Solution

The correct option is B Vc2(s)Vi(s)=sC1(sC1+sC2+s2C1C2R2)(1+sC1R1+s2C1L1)sC2


Applying KVL in loop-1,
Vi(s)=R1I1(s)+1sC1(I1(s)I2(s))+sL1I1(s) ...(i)
Vi(s)=I1(s)[R1+1sC1+sL1]I2(s)sC1 ...(ii)

Applying KVL in Loop-2

1sC1(I2(s)I1(s))+Vc2(s)+R2I2(s)=0 ....(iii)

Vc2(s)I1(s)sC1+I2(s)(1sC1+R2)=0 ...(iv)


Vc2(s)=I2(s)sC2 ...(v)

I2(s)=sC2Vc2(s) ...(vi)

From equation (vi) and (iv), we get

Vc2(s)I1(s)sc1+sC2Vc2(1sC1+R2)=0 ...(vii)

I1(s)=sC1Vc2(s)(1+sC2(1sC1+R2)) ...(viii)

I1(s)=sC1Vc2(s)(sC1+sC2+s2C1C2R2sC1) ...(ix)

I1(s)=Vc2(s)(sC1+sC2+s2C1C2R2) ....(x)


Substitue equation (vi) and equation (x) in equation (ii), we get

Vi(s)=Vc2(s)(sC1+sC2+s2C1C2R2)(R1+1sC1+sL1)sC2Vc2(s)sC1 ....(xi)

Vi(s)=Vc2(s)(sC1+sC2+s2C1C2R2)(1+sC1R1+s2L1C1)sC1sC2Vc2(s)sC1 ...(xiii)

The transfer function is

Vc2(s)Vi(s)=sC1(sC1+sC2+s2C1C2R2)(1+sC1R1+s2C1L1)sC2

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