Question

What is the units digit of $\left(2{)}^5\right(3{)}^3(4{)}^2$?

• A. $6$
• B. $4$
• C. $8$
• D. $2$

Answer 1

The correct option is B $4$

Use the last digit shortcut, ignoring all digits but the last in any intermediate products:

Step 1: $2^5=32$ Drop the tens digit and keep only the last digit: 2.

Step 2: $3^3=27$ Drop the tens digit and keep only the last digit: 7.

Step 3: $4^2=16$ Drop the tens digit and keep only the last digit: 6.

Step 4: $2\times 7\times 6=84$ Multiply the last digits of each of the products and keep only the last digit: 4.