What is the value obtained when we expand 1-32-

The correct option is D 4+2√(3) (1 + √(3))^2 = (1 + √(3))(1+ √(3)) = 1 + 2√(3) + 3 = 4 + 2√(3) ...

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Byju's Answer

Standard IX

Mathematics

Addition and Subtraction of Like and Unlike Surds

What is the v...

Question

What is the value obtained when we expand $({1 + \sqrt{3})}^{2}$ ?

$3 + 2 \sqrt{3}$

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$4 + 2 \sqrt{3}$

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$2 \sqrt{3}$

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Solution

The correct option is C
$4 + 2 \sqrt{3}$

${(1 + \sqrt{3})}^{2} = (1 + \sqrt{3}) (1 + \sqrt{3})$
$= 1 + 2 \sqrt{3} + 3 = 4 + 2 \sqrt{3}$

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Similar questions

Q. What is the value obtained when we expand

({1 + \sqrt{3})}^{2}

Q. What is the value obtained when we expand (1+(2^1/2))^2?

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(i) ; (ii) .

Q. If

\frac{\sqrt{2} + \sqrt{3}}{\sqrt[3]{2} - \sqrt[2]{3}} = a - b \sqrt{6}

, find the values of a and b.

Simplify:

$(i) {{(\frac{1}{3})}^{- 3} - {(\frac{1}{2})}^{- 3}} \div {(\frac{1}{4})}^{- 3} (i i) (3^{2} - 2^{2}) \times {(\frac{2}{3})}^{- 3} (i i i) {(\frac{1}{2}) \times (- 4)^{- 1}}^{- 1} (i v) {[{{(\frac{- 1}{4})}^{2}}^{- 2}]}^{- 1} (v) {{(\frac{2}{3})}^{2}}^{3} \times {(\frac{1}{3})}^{- 4} \times 3^{- 1} \times 6^{- 1}$

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What is the value obtained when we expand (1+√3)2?

The correct option is C 4+2√3 (1+√3)2=(1+√3)(1+√3) =1+2√3+3=4+2√3

What is the value obtained when we expand $({1 + \sqrt{3})}^{2}$ ?

The correct option is C
$4 + 2 \sqrt{3}$

${(1 + \sqrt{3})}^{2} = (1 + \sqrt{3}) (1 + \sqrt{3})$
$= 1 + 2 \sqrt{3} + 3 = 4 + 2 \sqrt{3}$