What is the value obtained when we expand 1-32 -

The correct option is C 4+2√(3)Using the identity, nbsp;(a+b)^2 = a^2+b^2+2ab nbsp;(1 + √(3))^2 nbsp;= 1^2 + (√(3))^2 + 2√(3) = 1+3 nbsp;+ 2√(3)= 4+2 ...

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Byju's Answer

Standard IX

Mathematics

Addition and Subtraction of Surds

What is the v...

Question

What is the value obtained when we expand $({1 + \sqrt{3})}^{2}$ ?

3 + 2 \sqrt{3}

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4 + 2 \sqrt{3}

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2 \sqrt{3}

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Solution

The correct option is C $4 + 2 \sqrt{3}$
Using the identity, $(a + b)^{2} = a^{2} + b^{2} + 2 a b$
${(1 + \sqrt{3})}^{2} = 1^{2} + (\sqrt{3})^{2} + 2 \sqrt{3} = 1 + 3 + 2 \sqrt{3} = 4 + 2 \sqrt{3}$

Suggest Corrections

What is the value obtained when we expand (1+√3)2?

The correct option is C 4+2√3Using the identity, (a+b)2=a2+b2+2ab (1+√3)2=12+(√3)2+2√3=1+3+2√3=4+2√3

What is the value obtained when we expand $({1 + \sqrt{3})}^{2}$ ?

The correct option is C $4 + 2 \sqrt{3}$
Using the identity, $(a + b)^{2} = a^{2} + b^{2} + 2 a b$
${(1 + \sqrt{3})}^{2} = 1^{2} + (\sqrt{3})^{2} + 2 \sqrt{3} = 1 + 3 + 2 \sqrt{3} = 4 + 2 \sqrt{3}$