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Question

What is the value of 01+23+45+67.........+1617+1819+20.
2+4+6.......+20.

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Solution

S=01+23+45+67....+1617+1819+20S=(1+3+5+7+...+19)+(2+4+6+....+20)
To find S
Series:1+3+5+7+....+19a(firstterm)=1d(commondifference)=2an=a+(n1)d19=1+(n1)2n=1010termsinseries.S1=n2[2a+(n1)d]=102[2+(101)2]=100
To find S2
Series:2+4+6+...+20a=2,d=2an=a+(n1)d20=2+(n1)2n=10termsS2=n2[2a+(n1)d]=102[2×2+(9)2]=110

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