What is the value of 1-cos2 -cosec2 -

We know that, nbsp; sin^2 θ+cos^2θ=1 ⇒ 1 cos^2 θ=sin^2 θ So, (1 cos^2 θ)cosec^2 θ= sin^2θ cosec^2 θ nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; n ...

You visited us 4 times! Enjoying our articles? Unlock Full Access!

Introduction

What is the v...

Question

What is the value of $(1 - c o s^{2} θ) c o s e c^{2} θ$ ?

1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

- 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

\frac{{cos}^{2} θ + {tan}^{2} θ - 1}{{sin}^{2} θ}

θ

θ = 0

θ = π / 2

∣ ∣ ∣ ∣ ∣ \begin{matrix} 1 + s i n^{2} θ & c o s^{2} θ & 4 s i n 4 θ s i n^{2} θ & 1 + c o s^{2} θ & 4 s i n 4 θ s i n^{2} θ & c o s^{2} θ & 1 + 4 s i n 4 θ \end{matrix} ∣ ∣ ∣ ∣ ∣ = 0

θ

\frac{π}{2}

∣ ∣ ∣ ∣ ∣ \begin{matrix} 1 + {cos}^{2} θ & {sin}^{2} θ & 4 sin 4 θ {cos}^{2} θ & 1 + {sin}^{2} θ & 4 sin 4 θ {cos}^{2} θ & {sin}^{2} θ & 1 + 4 sin 4 θ \end{matrix} ∣ ∣ ∣ ∣ ∣ = 0

θ = \frac{a π}{b}

\frac{(b - 3)}{a}

θ

θ = 0

\frac{π}{2}

∣ ∣ ∣ ∣ ∣ \begin{matrix} 1 + {sin}^{2} θ & {cos}^{2} θ & 4 sin 4 θ {sin}^{2} θ & 1 + {cos}^{2} θ & 4 sin 4 θ {sin}^{2} θ & {cos}^{2} θ & 1 + 4 sin 4 θ \end{matrix} ∣ ∣ ∣ ∣ ∣ = 0

\sqrt{3} t a n θ = 1

s i n^{2} θ - c o s^{2} θ

Join BYJU'S Learning Program