What is the value of $(1 + i) (1 + i^{2}) (1 + i^{3}) (1 + i^{4})$ ?

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Solution

$(1 + i) (1 + i^{2}) (1 + i^{3}) (1 + i^{4})$
we know $i^{2} = - 1$
$i^{3} = - i$
and $i^{4} = 1$
then
$(1 + i) (1 - 1) (1 - i) (1 + 1)$
$\Rightarrow (1 + i) (0) (1 - i) (2)$
=0

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Similar questions

(1 + i) (1 + i^{2}) (1 + i^{3}) (1 + i^{4})

(1 + i) (1 + i^{2}) (1 + i^{3}) (1 + i^{4})

$The value of (1 + i) (1 + i^{2}) (1 + i^{3}) (1 + i^{4}) is$

i^{18} - {3.1}^{7} + i^{2} (1 + i^{4}) (- i)^{26}

A B C D

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I_{1}, I_{2}, I_{3} & I_{4}

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