What is the value of 1 - 1 -2 - 2 -3 - 3 - - - n - n - where n- means n factorial or nn-1n-2 - 1A- n-1 -1B- n-1 -C- n -1D- None of these

The correct option is A (n+1)! 1 n*n! = (n+1 1)*n! = (n+1)! n! So ∑n*n! = (n+1)! 1 ...

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What is the value of $1 \times 1! + 2 \times 2! + 3 \times 3! + . . . . . . . . . . . . n \times n!$ ; where n! means n factorial or n(n-1)(n-2)...1

(n+1)!-1

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(n+1)!

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n!-1

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None of these

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What is the value of $1 \times 1! + 2 \times 2! + 3 \times 3! + . . . . . . . . . . . . n \times n!$ ; where n! means n factorial or n(n-1)(n-2)...1

The sum of (n+1) terms of $\frac{1}{2} + \frac{1}{1 + 2} + \frac{1}{1 + 2 + 3} + . . . . . . . . . .$ is

\frac{C_{0}}{2} - \frac{C_{1}}{3} + \frac{C_{2}}{4} - \frac{C_{3}}{5} + \dots

2 \leq {(1 + \frac{1}{n})}^{n} < 3, n \geq 1

n^{n + 1} > (n + 1)^{n}, n \geq 3, n ϵ N

\sum_{r = 1}^{n} (r^{2} + 1) r!

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