The correct option is C 1,234,321
To find the square of numbers that consist of repeated 1's such as 112, 1112, 1,1112, etc.:
∙ Count the number of 1's in the given number;
∙ Write starting from 1 till the number of 1's;
∙ Concatenate the reverse counting upto 1 with the last digit
For an example, let's say we need to find 1112:
∙ 111 consists of three 1's;
∙ Write starting from 1 till the number of 1's; hence, 123––––;
∙ Concatenate the reverse counting upto 1 with the last digit; hence, 12321–––
∴1112=12,321––––––––––––––––
Finally, we need to find the value of 1,1112.
∙ 1,111 consists of four 1's;
∙ Write starting from 1 till the number of 1's; hence, 1234–––––;
∙ Concatenate the reverse counting upto 1 with the last digit; hence, 1234321––––
∴1,1112=1,234,321––––––––––––––––––––––
Therefore, option (c.) is the correct answer.