What is the value of ${((2)^{- 1})}^{- 2}$ ?

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Solution

$2^{- 1}$ = $\frac{1}{2}$
${((2)^{- 1})}^{- 2}$ = $(\frac{1}{2})^{- 2}$ = ${(\frac{1}{(\frac{1}{2})})}^{2}$ = $(\frac{2}{1})^{2}$ = $2^{2}$ = 4

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