Question

What is the value of:
$3\frac{1}{12}-[1\frac{3}{4}+\{2\frac{1}{2}-(1\frac{1}{2}-\frac{1}{3})\left\}\right]$

• A. 0.5
• B. 2
• C. 1
• D. 0

Answer 1

The correct option is D

0

$3\frac{1}{12}-[1\frac{3}{4}+\{2\frac{1}{2}-(1\frac{1}{2}-\frac{1}{3})\left\}\right]$
$=\frac{37}{12}-[\frac{7}{4}+\frac{5}{2}-(\frac{3}{2}-\frac{1}{3}\left)\right]$

$=\frac{37}{12}-[\frac{7}{4}+\frac{5}{2}-\frac{3}{2}+\frac{1}{3}]$
$=\frac{37}{12}-[\frac{7}{4}+1+\frac{1}{3}]$
$=\frac{37}{12}-[\frac{11}{4}+\frac{1}{3}]$
$=\frac{37}{12}-\left[\frac{33+4}{12}\right]$
$=\frac{37}{12}-\frac{37}{12}$
$=0$