What is the value of -5-2-2-2-2-3 -658689698589

The correct option is B 689By the Laws of Exponents, nbsp; (a^m)^n=a^mn. So, (5^2)^2=5^4=5×5×5×5=625 (2^2)^3=2^6=2×2×2×2×2×2=64 ⇒(5^2)^2+(2^2)^3=625+64=689 ...

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Standard VII

Mathematics

Exponent of Exponent

What is the v...

Question

What is the value of $(5^{2})^{2} + (2^{2})^{3}$ ?

658

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689

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698

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589

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Solution

The correct option is B 689
By the Laws of Exponents, $(a^{m})^{n} = a^{m n}$ .

So, $(5^{2})^{2} = 5^{4} = 5 \times 5 \times 5 \times 5 = 625$
$(2^{2})^{3} = 2^{6} = 2 \times 2 \times 2 \times 2 \times 2 \times 2 = 64$

$\Rightarrow (5^{2})^{2} + (2^{2})^{3} = 625 + 64 = 689$

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Q. What is the value of

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What is the value of (52)2+(22)3 ?

The correct option is B 689By the Laws of Exponents, (am)n=amn. So, (52)2=54=5×5×5×5=625 (22)3=26=2×2×2×2×2×2=64 ⇒(52)2+(22)3=625+64=689

What is the value of $(5^{2})^{2} + (2^{2})^{3}$ ?

The correct option is B 689
By the Laws of Exponents, $(a^{m})^{n} = a^{m n}$ .

So, $(5^{2})^{2} = 5^{4} = 5 \times 5 \times 5 \times 5 = 625$
$(2^{2})^{3} = 2^{6} = 2 \times 2 \times 2 \times 2 \times 2 \times 2 = 64$

$\Rightarrow (5^{2})^{2} + (2^{2})^{3} = 625 + 64 = 689$