What is the value of 6 tan 2 -6 cos 2 - -

We have, We know that, Therefore, 6 nbsp;tan2θ 6cos2θ= 6 ...

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Complementary Trigonometric Ratios

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What is the value of $6 \tan^{2} θ - \frac{6}{\cos^{2} θ}$ .

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6 {tan}^{2} θ + 54 {cot}^{2} θ + 18

I.

54

A . M . \geq G . M .

6 {tan}^{2} θ, 54 {cot}^{2} θ, 18

II.

54

A . M . \geq G . M .

6 {tan}^{2} θ, 54 {cot}^{2} θ; 18

III.

78

{tan}^{2} θ = {cot}^{2} θ

32 t a n^{8} θ = 2 c o s^{2} α - 3 c o s α a n d 3 c o s^{3} θ + 6 c o s^{2} θ - 2 c o s θ - 4 = 0

α

Prove that $tan 4 θ = \frac{4 tan θ (1 - {tan}^{2} θ)}{1 - 6 {tan}^{2} θ + {tan}^{4} θ}$

6 cos 2 θ + 2 {cos}^{2} θ / 2 + 2 {sin}^{2} θ = 0, - π < θ < π

\int \frac{sin θ . sin 2 θ ({sin}^{6} θ + {sin}^{4} θ + {sin}^{2} θ) \sqrt{2 {sin}^{4} θ + 3 {sin}^{2} θ + 6}}{1 - cos 2 θ} d θ

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c

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