What is the value of $b^{2} - 5$ when $b = 5$ ?

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Solution

$b^{2} - 5 = 5^{2} - 5 = 25 - 5 = 20$

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Similar questions

Q. If

{(5)}^{a + b} = 5 \times 25 \times 125

, what is the value of

{(a + b)}^{2}

Q. If

a = \frac{\sqrt{5} + 1}{\sqrt{5} - 1}

and

b = \frac{\sqrt{5} - 1}{\sqrt{5} + 1}

, then the value of

\frac{a^{2} + a b + b^{2}}{a^{2} - a b + b^{2}}

Question 5 (ii)

When a = 0, b = -1, find the value of the given expression:
$2 a^{2} + b^{2} + 1$

A \propto B^{2}

and when A = 8, B = 2.
If B = 5, then find the value of A.

If $a = \frac{\sqrt{5} + 1}{\sqrt{5} - 1} a n d b = \frac{\sqrt{5} - 1}{\sqrt{5} + 1}, t h e v a l u e o f (\frac{a^{2} + a b + b^{2}}{a^{2} - a b + b^{2}})$ is :

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What is the value of b2−5 when b=5 ?

b2−5=52−5=25−5=20

What is the value of $b^{2} - 5$ when $b = 5$ ?

$b^{2} - 5 = 5^{2} - 5 = 25 - 5 = 20$