What is the value of $Δ n_{g}$ if we consider the combustion of liquid ethanol if reactants and products are at 298 K?

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Solution

The correct option is A $- 1$
$C_{2} H_{5} O H_{(l)} + 3 O_{2 (g)} △ ⟶ 2 C O_{2 (g)} + 3 H_{2} O_{(l)} Δ n_{g} = 2 - 3 = - 1$

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Similar questions

Δ n_{g}

△ n

1 m o l e

298 K

2 P Q ⇌ P_{2} + Q_{2}; K_{1} = 2.5 \times 10^{5}

P Q + \frac{1}{2} R_{2} ⇌ P Q R; K_{2} = 5 \times 10^{- 3}

K_{3}

\frac{1}{2} P_{2} + \frac{1}{2} Q_{2} + \frac{1}{2} R_{2} ⇌ P Q R

298 K

298 K

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