What is the value of ax y-z -ay x-z - ay-ax z-

The correct option is A 1 =a^xy xza^xy yz÷ #160; a^yza^xz =a^xy xza^xy yz× #160; a^xza^yz =a^xy xz+xza^xy yz+yz =a^xya^xy =1 ...

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Standard X

Mathematics

Centroid Formula

What is the v...

Question

What is the value of $\frac{a^{x (y - z)}}{a^{y (x - z)}} \div {(\frac{a^{y}}{a^{x}})}^{z}$ ?

1

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a^{x}

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a^{x y}

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a^{x y z}

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Solution

The correct option is A $1$
$= \frac{a^{x y - x z}}{a^{x y - y z}} \div \frac{a^{y z}}{a^{x z}}$

$= \frac{a^{x y - x z}}{a^{x y - y z}} \times \frac{a^{x z}}{a^{y z}}$

$= \frac{a^{x y - x z + x z}}{a^{x y - y z + y z}}$

$= \frac{a^{x y}}{a^{x y}}$

$= 1$

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Similar questions

Q. In the following figure,

∠ A X Y = ∠ A Y X .

\frac{B X}{A X} = \frac{C Y}{A Y},

then the triangle ABC is isosceles.

In the following figure, $∠$ AXY = $∠$ AYX. If $\frac{B X}{A X} = \frac{C Y}{A Y}$ , show that triangle ABC is isosceles.

In the following figure, $∠ A X Y = ∠ A Y X$ .

If $\frac{B X}{A X} = \frac{C Y}{A Y}$ , Prove that triangle ABC is an isosceles.

Find the factors of (a x + b y + b x + a z + a y + b z) .

$In the following figure, triangle AXY is isosceles with ∠ A X Y = ∠ A Y X .$

$If \frac{B X}{A X} = \frac{C Y}{A Y}, then prove that triangle ABC is an isosceles triangle.$

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What is the value of ax(y−z)ay(x−z)÷(ayax)z?

The correct option is A 1=axy−xzaxy−yz÷ayzaxz=axy−xzaxy−yz×axzayz=axy−xz+xzaxy−yz+yz=axyaxy=1

What is the value of $\frac{a^{x (y - z)}}{a^{y (x - z)}} \div {(\frac{a^{y}}{a^{x}})}^{z}$ ?

The correct option is A $1$
$= \frac{a^{x y - x z}}{a^{x y - y z}} \div \frac{a^{y z}}{a^{x z}}$

$= \frac{a^{x y - x z}}{a^{x y - y z}} \times \frac{a^{x z}}{a^{y z}}$

$= \frac{a^{x y - x z + x z}}{a^{x y - y z + y z}}$

$= \frac{a^{x y}}{a^{x y}}$

$= 1$