CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

What is the value of limxπ2[cosx] ?

Open in App
Solution

Let h be a very small positive number.
limxπ2[cos(π2h)][sinh]=0limxπ2[cosπ2]=0limxπ2[cos(π2+h)][cos(π2(h))][sin(h)]=1limxπ2+limxπ2Notcontinuous.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction to Limits
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon