What is the value of electron gain enthalpy of $N a^{+}$ if $I E_{1}$ of $N a$ = $5.1 e V$ ?

+ 10.2 e V

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- 5.1 e V

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10.2 e V

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+ 2.55 e V

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Solution

The correct option is A $- 5.1 e V$
$N a ⟶ {N a}^{+} + e^{-} Q = + 5.1 e V$

Thus $5.1 e V$ is the energy absorbed in this process.

$∴ N a^{+} + e^{-} ⟶ N a Q = - 5.1 e V$

i.e., the electron gain enthalpy of ${N a}^{+}$ is $- 5.1 e V$

Hence, the correct option is $B$

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Similar questions

{N a}^{+}

I E_{1}

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N a^{+}

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The first ionisation potential of Na is 5.1 eV. The value of electron gain enthalpy of $N a^{+}$ will be

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5.1 e V

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