What is the value of electron gain enthalpy of $N a^{+}$ if ${I.E.}_{1}$ of $N a = 5.1 e V$ ?

+ 2.55 e V

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+ 10.2 e V

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- 5.1 e V

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- 10.2 e V

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Solution

The correct option is C $- 5.1 e V$
Electron gain enthalpy is the reverse of ionisation energy.
Thus,
$Electron gain enthalpy of N a^{+} = - First ionisation energy of N a$

Hence, option (c) is the correct answer.

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