Question

What is the value of $\frac{1+i}{1-i}$ (give answer in 'i')

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Answer 1

$\frac{1+i}{1-i}$ can be brought to standard from by multiplying both numerator & denominator by $1+i$

So, $\frac{1+i}{1-i}.\frac{1+i}{1+i}$ = $\frac{(1+i{)}^2}{1^2-i^2}$ = $\frac{2i}{2}$ = $i$