Question

What is the value of given expression?

$\left[\right[3\times (-5)\times (-4)]÷27+(-13-4)]+[27\times (-2)÷(-3-3\left)\right]+[(-3)\times (-3)\times 5÷(-3\left)\right]]$

Answer 1

Find the value of the expression $\left[\right[3\times (-5)\times (-4)]÷27+(-13-4)]+[27\times (-2)÷(-3-3\left)\right]+[(-3)\times (-3)\times 5÷(-3\left)\right]]$.

According to the BODMAS rule in we the simplify any expression starting with solving bracket, then deal off operation, then Division, then multiplication, then addition and finally substraction operation is dealt as follow:

$\begin{array}{rcl}& & \left[\left[3\times \left\{\left(-5\right)\times \left(-4\right)\right\}\right]÷\left\{27+\left(-13-4\right)\right\}\right]+\left[\left\{27\times \left(-2\right)\right\}÷\left(-3-3\right)\right]+\left[\left\{\left(-3\right)\times \left(-3\right)\times \left(5\right)\right\}÷\left(-3\right)\right]\\ & =& \left[\left[3\times \left\{20\right\}\right]÷\left\{27+\left(-17\right)\right\}\right]+\left[\left\{-54\right\}÷\left(-6\right)\right]+\left[\left\{45\right\}÷\left(-3\right)\right]\\ & =& \left[60÷\left\{10\right\}\right]+\left(9\right)+\left(-15\right)\\ & =& 6+9-15\\ & =& 0\end{array}$

Hence, the value of the given expression is $0$.