You visited us 1 times! Enjoying our articles? Unlock Full Access!

Longest Chain Rule

What is the v...

Question

What is the value of gravitational potential at the surface of the earth, referred to zero potential at infinite distance? Given that the mass of the earth is 610²⁴ kg, radius of the earth is 6400 km and G=6.6710^-11 Nm²/kg² .

Open in App

Solution

Dear Student,

Gravitational potential is given as:

V=-GM/r
V=- (6.67 X 10^-11 X .6 X 10²⁴ )/ 6400 = 6.65 X 10¹⁰J kg^-1

Regards

Suggest Corrections

Similar questions

9.8 {m/s}^{2}

6400 km

[G = 6.67 \times 10^{- 11} {Nm}^{2} {/kg}^{2}]

1000

6.38 \times 10^{3}

= 6 \times 10^{24}

G = 6.67 \times 10^{- 11}

N m^{2}

k g^{- 2}

g

- 5.4 \times 10^{7} J {k g}^{- 2}

6.0 {m s}^{- 2}

6400 k m

- 5.4 \times 10^{7} J / k g^{2}

6 m / s^{2}

= 6 \times 10^{24}

= 6.67 \times 10^{11} N - m^{2} / {k g}^{2}

Join BYJU'S Learning Program