Question

What is the value of $k$ for which the HCF of $2x^2+kx-12$ and $x^2+x-2k-2$ is $(x+4)$?

• A. $5$
• B. $7$
• C. $10$
• D. $-4$

Answer 1

The correct option is A $5$

$(x+4)$ is HCF $\Rightarrow x=-4$ is As solution

of $2x^2+kx-12\&x^2+x-2x-2$

$\Rightarrow 2(-4{)}^2+k(-4)-12=0\Rightarrow k=5$

$\Rightarrow (-4{)}^2-4-2k-2=0\Rightarrow k=5$