What is the value of ${[2 - 3 {(2 - 3)}^{- 1}]}^{- 1}$ ?

5

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- 5

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\frac{1}{5}

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\frac{- 1}{5}

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Solution

The correct option is A $\frac{1}{5}$
$= {[2 - 3 {(2 - 3)}^{- 1}]}^{- 1}$
$= {[2 - 3 {(- 1)}^{- 1}]}^{- 1}$
$= {[2 - 3 (- 1)]}^{- 1}$
$= {[2 + 3]}^{- 1}$
$= {[5]}^{- 1}$
$= \frac{1}{5}$

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Similar questions

∣ ∣ ∣ ∣ \begin{matrix} 32 & 24 & 16 8 & 3 & 5 4 & 5 & 3 \end{matrix} ∣ ∣ ∣ ∣ = λ ∣ ∣ ∣ ∣ \begin{matrix} 1 & 3 & 2 2 & 3 & 5 1 & 5 & 3 \end{matrix} ∣ ∣ ∣ ∣

λ

\frac{1}{(216)^{- 2 / 3}} + \frac{1}{(256)^{- 3 / 4}} + \frac{1}{(32)^{- 1 / 5}}

\frac{1}{5} \div \frac{1}{5} \div \frac{1}{5} \div \frac{1}{5} \div \frac{1}{5} \div 5 \div 5 \div 5

\frac{2}{5} (5 x + 1) + \frac{3}{5} = 1

The value of $\frac{1}{{(216)}^{- \frac{2}{3}}} + \frac{1}{{(256)}^{- \frac{3}{4}}} + \frac{1}{{(32)}^{- \frac{1}{5}}}$ is :

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