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Question

What is the value of [(2.3)3−0.027(2.3)2+0.69+0.09]?

A
2.6
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B
2
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C
1.3
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D
1
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Solution

The correct option is B 2
[(2.3)3(0.3)3(2.3)2+(2.3)(0.3)+(0.3)2]=(2.30.3)[(2.3)2+(2.3)(0.3)+(0.3)2](2.3)2+(2.3)(0.3)+(0.3)2
(a3b3)=(ab)(a2+b2+ab)=2

1125114_552885_ans_7090f13cbda146718b176092c8a1259e.jpg

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