Question

What is the value of log K for the reaction at 298 K if $△G^0=63.3kJ$?

• A. -11.09
• B. -9.6
• C. -7.4
• D. -10.5

Answer 1

The correct option is A -11.09

${\Delta G}^0$ is related to $K_{sp}$ by the equation

${\Delta G}^0=-2.303RTlog{K}_{sp}$

We are given ${\Delta G}^0=63.3KJ=63300$ Joules

$63300=-\left(2.303\right)\left(8.314\right)\left(298\right)logK$

$logK=-11.09$

$\Rightarrow$ Value of $logK$ is $-11.09$.