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Question

What is the value of m if the vectors 2^i^j+^k,^i+2^j3^k and 3^i+m^j+5^k are coplanar?

A
-2
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B
2
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C
-4
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D
4
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Solution

The correct option is C -4
For any three vectors to be coplanar, scalar triple product should be zero.
So, we have

∣ ∣2111233m5∣ ∣=02×((2×5)(3×m))(1)((1×5)(3×3))+1×((1×m)(2×3))=020+6m+5+9+m6=0m=692057=4
So value of m is -4.

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