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Question

What is the value of mode for the following data:

Class intervalFrequency
350−36915
370−38927
390−40931
410−42919
430−44913
450−4696

A
390
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B
394.50
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C
394
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D
400
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Solution

The correct option is B 394.50

Class interval

Frequency

349.5−369.5

15

369.5−389.5

27

389.5−409.5

31

409.5−429.5

19

429.5−449.5

13

449.5−469.5

6


Mode is the value which occurs the highest number of times in a series.
Mode= L + [ (fm − fm-1)/{(fm − fm-1) + (fm − fm+1)}] × w
where
  • L is the lower class boundary of the modal group
  • fm-1is the frequency of the group before the modal group
  • fmis the frequency of the modal group
  • fm+1is the frequency of the group after the modal group
  • w is the group width
Therefore, in the given sum the modal class is 389.5−409.5 so
  • L = 389.5
  • fm-1= 27
  • fm= 31
  • fm+1= 19
  • w = 20
Mode = 389.5 + [(31 – 27)/{(31 − 27) + (31 − 19)}] × 20
= 389.5 + 5
= 394.50

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