What is the value of $n$ in the molecular formula of $B e_{n} A l_{2} S i_{6} O_{18}$ ?

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Solution

The given species is beryl.
Now, the charges on each elements are: $B e : + 2, A l : + 3, S i : + 4, O : - 2$
On balancing the charge, we get an equation:
$2 n + 6 + 24 - 36 = 0$
$\Rightarrow n = 3$
Thus, the formula is $B e_{3} A l_{2} S i_{6} O_{18}$ .

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B e_{n} A l_{2} S i_{6} O_{18}

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Q. The value of n in the molecular formula

B e_{n} A l_{2} S i_{6} O_{18}

Q. The value of n in the molecular formula

B e_{n} A l_{2} S i_{6} O_{18}

The molecules of alkene family are represented by a general formula $C_{n} H_{2 n}$ . Answer the following:
(a) What do n and 2n signify?
(b) What is the name of alkene when n = 4?
(c) What is the molecular formula of alkene when n = 4?
(d) What is the molecular formula of the alkene if there are ten H atoms in it?
(e) What is the structural formula of the third member of the alkene family?
(f) Write the molecular formula of lower and higher homologous of an alkene which contains four carbon atoms.

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What is the value of n in the molecular formula of BenAl2Si6O18? ​​​​​​​

The given species is beryl. Now, the charges on each elements are: Be:+2, Al:+3, Si:+4, O:−2 On balancing the charge, we get an equation: 2n+6+24−36=0 ⇒n=3 Thus, the formula is Be3Al2Si6O18.

What is the value of $n$ in the molecular formula of $B e_{n} A l_{2} S i_{6} O_{18}$ ?

The given species is beryl.
Now, the charges on each elements are: $B e : + 2, A l : + 3, S i : + 4, O : - 2$
On balancing the charge, we get an equation:
$2 n + 6 + 24 - 36 = 0$
$\Rightarrow n = 3$
Thus, the formula is $B e_{3} A l_{2} S i_{6} O_{18}$ .