Question

What is the value of (Negative $14$ Superscript $0$ Baseline) Superscript negative $2$?

Answer 1

Find the value of ${\left({\left(-14\right)}^0\right)}^{-2}$ :

Recall that: any non-zero number exponent zero is $1$.

Using this property, we simplify our expression to ${\left(1\right)}^{-2}$ since, ${\left(-14\right)}^0=1$

Now using the property of exponents

$a^{-n}=\frac{1}{a^n}$

This implies that

$$\begin{gathered} 1^{-2}=\frac{1}{1^2} \\ =\frac{1}{1} \\ =1 \end{gathered}$$

Hence, the value of ${\left({\left(-14\right)}^0\right)}^{-2}$ is equal to $1$.