What is the value of -A-B-A-B-

The correct option is A 0 Given, (A⃗+B⃗).(A⃗×B⃗)=A⃗.(A⃗×B⃗)+B⃗.(A⃗×B⃗) (A⃗+B⃗).(A⃗×B⃗)=0 Because A⃗×B⃗ is perpendicular to both A⃗ an ...

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Byju's Answer

Standard XII

Physics

Work Done as Dot Product

What is the v...

Question

What is the value of $(\to A + \to B) . (\to A \times \to B)$ ?

0

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A^{2} - B^{2}

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A^{2} + B^{2} + 2 A B

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None of these

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Solution

The correct option is A $0$
Given,
$(\to A + \to B) . (\to A \times \to B) = \to A . (\to A \times \to B) + \to B . (\to A \times \to B)$
$(\to A + \to B) . (\to A \times \to B) = 0$
Because $\to A \times \to B$ is perpendicular to both $\to A$ and $\to B$ . And as we know that the dot product of two perpendicular vector is zero.
The correct option is A.

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Similar questions

Simplify $\frac{a - b}{a} + \frac{a + b}{b}$

Q. If

\frac{a^{2} + 2 a b + b^{2}}{a^{2} - b^{2}} = 2 a + 2 b

, what is the value of

a - b

Which of the following is correct?
a) $(a - b)^{2} = a^{2} + 2 a b - b^{2}$
b) $(a - b)^{2} = a^{2} - 2 a b + b^{2}$
c) $(a - b)^{2} = a^{2} - b^{2}$
d) $(a + b)^{2} = a^{2} + 2 a b - b^{2}$

If $(a + b)^{2} = a^{2} + 2 a b + b^{2}$ then what is the value of $a^{2} + b^{2}$

Find:
$(a + b + c) \times (a + b - c) =$

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What is the value of (→A+→B).(→A×→B)?

The correct option is A 0Given,(→A+→B).(→A×→B)=→A.(→A×→B)+→B.(→A×→B)(→A+→B).(→A×→B)=0Because →A×→B is perpendicular to both →A and →B. And as we know that the dot product of two perpendicular vector is zero. The correct option is A.

What is the value of $(\to A + \to B) . (\to A \times \to B)$ ?