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Standard VIII

Mathematics

Relation for Direct Proportion

What is the v...

Question

What is the value of $p_{1}$ and $m_{2}$ ?
m (kg) v (m/s) p = mv (kgm/s)
85 60 $p_{1}$
$m_{2}$ 2.5 6.25

5100, 2.5

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5.1 , 2.5

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2500, 5

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55, 2.6

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Solution

The correct option is A 5100, 2.5
m (kg) v (m/s) p = mv (kgm/s)
85 60 5100
2.5
2.5 6.25
In first case:
$m = 85 k g$
$v = 60 m / s$
$p = m v = 85 \times 60 = 5100 k g m / s$
In second case:
$m = ?$
$v = 2.5 m / s$
$p = m v = 6.25$
$∴ m = \frac{p}{v} = \frac{6.25}{2.5} = 2.5 k g$

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What is the value of p1 and m2 ?m (kg)v (m/s)p = mv (kgm/s)8560p1m22.56.25

The correct option is A 5100, 2.5m (kg)v (m/s)p = mv (kgm/s)856051002.52.56.25In first case:m=85kgv=60m/sp=mv=85×60=5100 kgm/sIn second case:m=?v=2.5m/sp=mv=6.25∴m=pv=6.252.5=2.5 kg

What is the value of $p_{1}$ and $m_{2}$ ?
m (kg) v (m/s) p = mv (kgm/s)
85 60 $p_{1}$
$m_{2}$ 2.5 6.25

The correct option is A 5100, 2.5
m (kg) v (m/s) p = mv (kgm/s)
85 60 5100
2.5
2.5 6.25
In first case:
$m = 85 k g$
$v = 60 m / s$
$p = m v = 85 \times 60 = 5100 k g m / s$
In second case:
$m = ?$
$v = 2.5 m / s$
$p = m v = 6.25$
$∴ m = \frac{p}{v} = \frac{6.25}{2.5} = 2.5 k g$