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Question

What is the value of p that satisfies the equation 4+3(p−1)=10?

A
2
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B
3
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C
4
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D
6
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Solution

The correct option is B 3
Given expression:
4+3(p1)=10

Transposing 4 to the other side, we have

3(p1)=104
3(p1)=6

Dividing both sides with 3, we have

3(p1)3=63
p1=2

Transposing 1 to the other side, we have
p=2+1=3

Hence, the value of p that satisfies the given equation = 3

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