Question

What is the value of refractive index of the medium if the critical angle of incidence in a denser – rarer inter face is equal to 45450?

Answer 1

$$\begin{gathered} Relationbetweenrefractiveindexandcriticalangle. \\ \mu =\frac{1}{\sin C} \\ wherevCisthecritialangle \\ \mu =\frac{1}{\sin 45} \\ \mu =1.414 \end{gathered}$$