What is the value of - sin 90^., - sin 120^.?

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Solution

- Sin 90 = - 1, as Sin 90 = 1
- Sin 120 = - Sin (90 + 30) = - Cos 30 = $- \sqrt{\frac{3}{4}}$ , as Sin(90 + A) = Cos A

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Similar questions

s i n^{2} 0 + s i n^{2} +

+ s i n^{2} 90

{sin}^{2} (120 + θ) + {sin}^{2} (120 - θ)

The value of sin120^o cos60^o+ cos120^o sin60^ois equal to

s i n^{2} (120^{\circ} + θ) + s i n^{2} (120^{\circ} - θ)

120^{\circ}

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