What is the value of sin - for the given right triangle- right angled at B -A- 3 - 5B- 5 - 3C- 4 - 5D- 3 - 4

The correct option is C 4/5 sinθ =Opposite side/Hypotenuse = BC/AC = 4/5 ...

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Ratio of Sides of Special Triangles

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What is the value of sin $θ$ for the given right triangle, right angled at B?

3/5

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5/3

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4/5

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3/4

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What is the value sin $θ$ in the given right triangle, right angled at B?

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