Question

What is the value of $\sqrt[3]{38}+\frac{1}{\sqrt[3]{38}}$ ?

• A. 2
• B. 2.5
• C. 0.5
• D. 1

Answer 1

The correct option is B

2.5

$\sqrt[3]{38}+\frac{1}{\sqrt[3]{38}}$
Cube root of $8=2$
So, the given expression can be written as ​$\sqrt[3]{32^3}+\frac{1}{\sqrt[3]{32^3}}$

So, $2+\frac{1}{2}=2.5$