Question

What is the value of $\sqrt[3]{38}+\frac{1}{\sqrt[3]{38}}$ ?

• A. 2
• B. 2.5
• C. $\frac{5}{2}$
• D. $\frac{2}{5}$

Answer 1

Answer: (B), (C)

The correct options are
B

2.5

C

$\frac{5}{2}$

$\sqrt[3]{38}+\frac{1}{\sqrt[3]{38}}$

8 = $2\times 2\times 2$ = $2^3$
Cube root of 8 = 2
So, the given expression can be written as ​$\sqrt[3]{32^3}+\frac{1}{\sqrt[3]{32^3}}$

So, $2+\frac{1}{2}=\frac{4+1}{2}=\frac{5}{2}=2.5$ ( taking 2 as the LCM )